Two mangos cost as much as five oranges. Mr. Lim bought 3 mangos and five oranges for $25. How much should Mr. Lim pay if he bought 9 mangos? Make sure a second grader can understand your steps!
To solve this problem, we need to find the cost of one mango.
Step 1: Let's assume the cost of one mango is "x" dollars.
Step 2: We are given that two mangos cost as much as five oranges, so the cost of one mango is equal to (5/2) times the cost of one orange.
Step 3: Therefore, one orange costs (1/5) times the cost of one mango, or (1/5)x dollars.
Step 4: Mr. Lim bought 3 mangos, so the cost of three mangos is 3x dollars.
Step 5: Mr. Lim also bought five oranges, so the cost of five oranges is (5/5)x dollars, which simplifies to x dollars.
Step 6: The total cost of three mangos and five oranges is 3x + x = 4x dollars.
Step 7: We are given that the total cost of three mangos and five oranges is $25, so 4x = 25.
Step 8: To find the cost of one mango, we divide both sides of the equation by 4: x = 25/4 = $6.25.
Step 9: Finally, if Mr. Lim bought 9 mangos, the total cost of the 9 mangos is 9 * $6.25 = $56.25.
Therefore, Mr. Lim should pay $56.25 if he bought 9 mangos.