In triangle ARP, centroid E is on median AX. AE = y+6 and EX = 3y-2. Find AX
To find AX, we need to find the length of AE and EX and then sum them.
Given that AE = y+6 and EX = 3y-2, we can add them together:
AE + EX = (y+6) + (3y-2)
= y + 3y + 6 - 2
= 4y + 4
Therefore, AX = AE + EX = 4y + 4.