In Triangle ARP, centroid E is on median AX¯¯¯¯¯¯¯¯
. AE = y+6 and EX = 3y-2. Find AX
(1 point)
Responses
7/3
5 1/2
13
11
I just watched pain happen what the heck
"Let's choose an answer out of the given options." *Proceeds to choose an answer that IS NOT one of the given options*
The given options are
11
13
7/3
5 1/2
The given option are NOT
12
14
Clearly none of the given options are 14, so OUT OF THE GIVEN OPTIONS
Those being
11
13
7/3
5 1/2
WHAT IS THE ANSWER
Again, the given options are
11
13
7/3
5 1/2
12 isn't an option
Apologies for the incorrect response. Let's review the problem again to find the correct answer.
Given:
AE = y + 6
EX = 3y - 2
In a triangle with centroid E, the centroid divides the median into segments in a 2:1 ratio. This means that AE is twice as long as EX:
AE = 2 * EX
Substitute the given expressions for AE and EX:
y + 6 = 2(3y - 2)
Now, solve for y:
y + 6 = 6y - 4
5y = 10
y = 2
Now that we have the value of y, we can find AE and EX:
AE = y + 6 = 2 + 6 = 8
EX = 3y - 2 = 3(2) - 2 = 4
To find AX, we add AE and EX:
AX = AE + EX = 8 + 4 = 12
Therefore, the length of segment AX is 12.
In Triangle ARP, centroid E is on median AX¯¯¯¯¯¯¯¯
. AE = y+6 and EX = 3y-2. Find AX
7/3
5 1/2
13
11
To find AX, we need to find the lengths of AE and EX, and then add them together.
Given:
AE = y + 6
EX = 3y - 2
We know that in a triangle with a centroid, the centroid divides the median into segments in a 2:1 ratio. This means that AE is twice as long as EX:
AE = 2 * EX
Substitute the given expressions for AE and EX:
y + 6 = 2(3y - 2)
Now, solve for y:
y + 6 = 6y - 4
5y = 10
y = 2
Now that we have the value of y, we can find AE and EX:
AE = y + 6 = 2 + 6 = 8
EX = 3y - 2 = 3(2) - 2 = 4
To find AX, we add AE and EX:
AX = AE + EX = 8 + 4 = 12
Therefore, the length of segment AX is 12. However, 12 is not one of the given answer options. There might be an error in the problem statement or options provided.
Redo your math please
7/3
5 1/2
13
11
Apologies for the confusion. Let's redo the math:
Given:
AE = y + 6
EX = 3y - 2
We know that in a triangle with a centroid, the centroid divides the median into segments in a 2:1 ratio. This means that AE is twice as long as EX:
AE = 2 * EX
Substitute the given expressions for AE and EX:
y + 6 = 2(3y - 2)
Now, solve for y:
y + 6 = 6y - 4
5y = 10
y = 2
Now that we have the value of y, we can find AE and EX:
AE = y + 6 = 2 + 6 = 8
EX = 3y - 2 = 3(2) - 2 = 4
To find AX, we add AE and EX:
AX = AE + EX = 8 + 4 = 12
Thus, the correct answer is 12.
In Triangle ARP, centroid E is on median AX. AE = y+6 and EX + 3y-2. Find AX
11
13
7/3
5 1/2
12 is NOT an option, please choose an answer OTHER THAN 12, being 11, 13, 7/3, or 5 1/2