In Triangle ARP, centroid E is on median AX¯¯¯¯¯¯¯¯
. AE = y+6 and EX = 3y-2. Find AX
A7/3
B 5 1/2
C 13
D 11
Let AX = a.
Since E is the centroid, AE = 2EX.
Therefore, y + 6 = 2(3y - 2).
Simplifying the equation, we get y + 6 = 6y - 4.
Rearranging the equation, we get 5y = 10.
Dividing both sides by 5, we get y = 2.
Substituting the value of y into the equation AE = y + 6, we get AE = 8.
Since E is the centroid, AX = 3AE.
Therefore, AX = 3(8) = 24.
Hence, the answer is AX = 24, which corresponds to option D.