Add: (4d−3)+(12d+4) . (1 point)
To add (4d−3)+(12d+4), we can combine like terms.
First, let's focus on the terms with the variable d.
We have 4d and 12d. When we add these together, we get 16d.
Next, let's look at the constant terms.
We have -3 and 4. When we add these together, we get 1.
Putting it all together, the sum is 16d + 1.
Add: (2m−3)+(3n−1)+(3m+1) .(1 point)
To add (2m−3)+(3n−1)+(3m+1), we can combine like terms.
First, let's focus on the terms with the variable m.
We have 2m and 3m. When we add these together, we get 5m.
Next, let's look at the terms with the variable n.
We have 3n. There are no other n terms to combine it with.
Now, let's look at the constant terms.
We have -3, -1, and 1. When we add these together, we get -3.
Putting it all together, the sum is 5m + 3n - 3.
Subtract: 2(10b+4)−(b−2) .(1 point)
To subtract 2(10b+4)−(b−2), we can distribute the 2 to all the terms inside the parentheses.
First, let's distribute the 2 to (10b+4):
2 * 10b = 20b
2 * 4 = 8
So, 2(10b+4) becomes 20b + 8.
Now, let's subtract (b−2):
We can remove the parentheses since there is no distribution involved.
So, (b - 2) remains as it is.
Now, let's subtract the two terms:
20b + 8 - (b - 2)
To subtract a term, we can change the sign and add.
So, it becomes:
20b + 8 - b + 2
Now, let's combine like terms:
(20b - b) + (8 + 2)
19b + 10
Therefore, the subtraction of 2(10b+4)−(b−2) is 19b + 10.
Subtract: (3g−4)−2(3g+4) .(1 point)
To subtract (3g−4)−2(3g+4), we can distribute the -2 to all the terms inside the parentheses.
First, let's distribute the -2 to (3g+4):
-2 * 3g = -6g
-2 * 4 = -8
So, -2(3g+4) becomes -6g - 8.
Now, let's subtract (3g−4):
We can remove the parentheses since there is no distribution involved.
So, (3g - 4) remains as it is.
Now, let's subtract the two terms:
(3g - 4) - (-6g - 8)
To subtract a term that is being subtracted, we can change the sign and add.
So, it becomes:
3g - 4 + 6g + 8
Now, let's combine like terms:
(3g + 6g) + (-4 + 8)
9g + 4
Therefore, the subtraction of (3g−4)−2(3g+4) is 9g + 4.
wrong
Apologies for the mistake. Let's correct the calculation.
To subtract (3g−4)−2(3g+4), we will distribute the -2 to both terms within the second set of parentheses.
First, distribute the -2 to (3g+4):
-2 * 3g = -6g
-2 * 4 = -8
Thus, 2(3g+4) becomes -6g - 8.
Now, let's subtract (3g−4) from -6g-8:
(3g-4) - (-6g-8)
To remove the double negative, we can change the subtraction to addition and change the sign of the term being subtracted:
(3g-4) + 6g + 8
Now, let's combine like terms:
3g + 6g - 4 + 8
This simplifies to:
9g + 4
Therefore, (3g−4)−2(3g+4) equals 9g + 4.