Add: (4d−3)+(12d+4) .

To add (4d−3) and (12d+4), we combine like terms by adding the coefficients of d and the constant terms separately.

The coefficient of d in (4d−3) is 4.
The coefficient of d in (12d+4) is 12.

Adding the coefficients of d, we get 4 + 12 = 16d.

The constant term in (4d−3) is -3.
The constant term in (12d+4) is 4.

Adding the constant terms, we get -3 + 4 = 1.

Therefore, (4d−3)+(12d+4) simplifies to 16d + 1.