Use the equation of motion to answer the question. x=x0+v0t+12at2 An object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s? (1 point) Responses 5.5 m 5.5 m 11 m 11 m 18 m 18 m 9 m
To find the final position of the object after 2 seconds, we need to substitute the given values into the equation of motion:
x = x0 + v0t + (1/2)at²
Given:
x0 = 2 m (starting position)
v0 = 4.5 m/s (starting velocity)
a = 0 m/s² (no acceleration)
t = 2 s (time)
Plugging the values into the equation, we have:
x = 2 + (4.5)(2) + (1/2)(0)(2²)
x = 2 + 9 + 0
x = 11
Therefore, the final position of the object after 2 seconds is 11 m.
Is this right
Apologies for the confusion in my previous response. Since the given acceleration is zero, the equation of motion simplifies to:
x = x0 + v0t
Plugging in the given values:
x = 2 + (4.5)(2)
x = 2 + 9
x = 11
Therefore, the correct answer is 11 m.
To find the final position of the object after 2 seconds using the equation of motion, you need to substitute the given values into the equation.
The equation of motion is: x = x0 + v0t + (1/2)at^2
Given:
Initial position (x0) = 2 m
Initial velocity (v0) = 4.5 m/s
Acceleration (a) = 0 m/s^2 (no acceleration)
Time (t) = 2 s
Substituting these values into the equation, we have:
x = 2 + 4.5 * 2 + (1/2) * 0 * (2^2)
x = 2 + 9
x = 11 m
Therefore, the final position of the object after 2 seconds is 11 m.