Dee has at most $150 to spend on restocking dolls and trains at her toy store.
Dolls cost $7.50, and trains cost $5.00. Dee needs at least 8 dolls, and no more than 10 trains.
solve
Let's assume Dee buys x dolls and y trains.
The cost of x dolls is 7.50x dollars.
The cost of y trains is 5.00y dollars.
We are given that Dee needs at least 8 dolls, so x ≥ 8.
We are also given that Dee can have no more than 10 trains, so y ≤ 10.
The total cost, C, is the sum of the cost of dolls and the cost of trains:
C = 7.50x + 5.00y
We are also given that Dee has at most $150 to spend, so the total cost must be at most $150:
C ≤ 150
Substituting the expression for C from above:
7.50x + 5.00y ≤ 150
Combining the inequalities x ≥ 8 and y ≤ 10, we can solve for the maximum and minimum values of the total cost.
Minimum total cost:
For the minimum total cost, we will assume Dee buys the minimum number of dolls (8) and the maximum number of trains (10).
C = 7.50(8) + 5.00(10)
C = 60 + 50
C = 110
So, the minimum total cost is $110.
Maximum total cost:
For the maximum total cost, we will assume Dee buys the maximum number of dolls (10) and the minimum number of trains (8).
C = 7.50(10) + 5.00(8)
C = 75 + 40
C = 115
So, the maximum total cost is $115.
Thus, the total cost of restocking dolls and trains at Dee's toy store is between $110 and $115.