How long would it take Jesse with an acceleration of -2.50 (m/s^2) to bring his bicycle with an initial velocity of 13.5 (m/s) to a complete stop
We can use the following kinematic equation to solve this problem:
vf^2 = vi^2 + 2ad
where:
- vf = final velocity (in this case, 0 m/s, since Jesse wants to bring his bicycle to a complete stop)
- vi = initial velocity (13.5 m/s)
- a = acceleration (-2.50 m/s^2)
- d = displacement (unknown in this case)
Rearranging the equation, we get:
d = (vf^2 - vi^2) / (2a)
Substituting the given values, we have:
d = (0 - 13.5^2) / (2 * -2.50)
= (0 - 182.25) / (-5.00)
= 182.25 / 5.00
= 36.45 meters
Therefore, it would take Jesse approximately 36.45 meters to bring his bicycle to a complete stop with an acceleration of -2.50 m/s^2.