How long would it take Jesse with an acceleration of -2.50 m/s2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
To determine how long it would take Jesse to bring his bicycle to a complete stop, we can use the equation for motion with constant acceleration:
v = u + at,
where:
- v is the final velocity (which is 0 m/s because he is coming to a stop),
- u is the initial velocity (which is 13.5 m/s),
- a is the acceleration (which is -2.50 m/s^2), and
- t is the time we want to find.
Rearranging the equation to solve for time, we have:
t = (v - u) / a.
Plugging in the given values, we get:
t = (0 - 13.5) / -2.50.
Calculating:
t = -13.5 / -2.50,
t = 5.4 seconds.
Therefore, it would take Jesse 5.4 seconds to bring his bicycle to a complete stop.
To determine how long it would take for Jesse to bring his bicycle to a complete stop, we can use the equation for motion with constant acceleration:
v = u + at
Where:
v = final velocity (in this case, 0 m/s as the bicycle comes to a complete stop)
u = initial velocity (13.5 m/s)
a = acceleration (-2.50 m/s^2)
t = time (what we're trying to find)
Plugging in the values we know:
0 = 13.5 + (-2.50)t
Now, let's solve for t:
-2.50t = -13.5
Dividing both sides by -2.50:
t = 13.5 / 2.50
Calculating:
t = 5.4 seconds
Therefore, it would take Jesse approximately 5.4 seconds to bring his bicycle to a complete stop with an acceleration of -2.50 m/s^2.