a bicycle and a rider together have a mass of 90kg. if the bicycle moves at 6.0 m/s, how much force is needed to bring it to a step in 5.0s ?

We can use the equation:

force = mass x acceleration

To find the force needed to bring the bicycle and rider to a stop, we need to first calculate the acceleration. We can use the equation:

acceleration = (final velocity - initial velocity) / time

The initial velocity is 6.0 m/s, the final velocity is 0 m/s (since we want to bring it to a stop), and the time is 5.0 s. Therefore:

acceleration = (0 m/s - 6.0 m/s) / 5.0 s = -1.2 m/s^2

The negative sign indicates that the acceleration is in the opposite direction of motion (i.e. slowing down).

Now we can use the first equation to find the force needed:

force = mass x acceleration = 90 kg x (-1.2 m/s^2) = -108 N

The negative sign indicates that the force is in the opposite direction of motion (i.e. resisting motion). Therefore, the force needed to bring the bicycle and rider to a stop is 108 N, and it acts in the direction opposite to the motion of the bicycle.

The mass of a rocket is 2.4 x 10^3 kilograms.

A. Find the mass of the rocket on the moon.
B. Compute for the weight of the rocket on the moon.

The mass of the rocket remains the same regardless of where it is located, since mass is a measure of the amount of matter in an object. However, the weight of the rocket changes depending on the gravitational force it experiences.

A. On the moon, the acceleration due to gravity is approximately 1.62 m/s^2, compared to 9.81 m/s^2 on Earth. To find the mass of the rocket on the moon, we can use the formula:

mass on moon = mass on Earth / acceleration due to gravity on the moon

mass on moon = (2.4 x 10^3 kg) / 1.62 m/s^2 = 1481.48 kg

Therefore, the mass of the rocket on the moon is approximately 1481.48 kg.

B. To find the weight of the rocket on the moon, we can use the formula:

weight on moon = mass on moon x acceleration due to gravity on the moon

weight on moon = (1481.48 kg) x (1.62 m/s^2) = 2394.38 N

Therefore, the weight of the rocket on the moon is approximately 2394.38 N.

To calculate the amount of force needed to bring the bicycle to a stop, we can use Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration. In this case, the acceleration is the change in velocity over time.

Given:
Mass of the bicycle and rider (m) = 90 kg
Initial velocity (u) = 6.0 m/s
Final velocity (v) = 0 m/s (bicycle comes to a stop)
Time taken (t) = 5.0 s

First, let's calculate the acceleration (a) using the equation:

a = (v - u) / t

Here, v is the final velocity, u is the initial velocity, and t is the time taken.

Substituting the given values:

a = (0 - 6.0) m/s / 5.0 s
a = -6.0 m/s / 5.0 s
a = -1.2 m/s²

Since the acceleration is negative, it indicates a deceleration (opposite to the direction of motion).

Now, we can calculate the force (F) using the equation:

F = m * a

Substituting the given mass and acceleration:

F = 90 kg * (-1.2 m/s²)
F = -108 N

The negative sign indicates that the force is in the opposite direction of motion, to bring the bicycle to a stop.

Therefore, the force needed to bring the bicycle to a stop is 108 N in the opposite direction of motion.