An object with a charge of +1 C is 10 mm from an object with a charge of +1 C. Based on the data in the table, which type and amount of electrical force will there most likely be between the two objects?
repulsive, strong
repulsive, weak
attractive, weak
attractive, strong
To determine the type and amount of electrical force between the two objects, we can use Coulomb's law. Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Here, we have two objects, each with a charge of +1 C, and they are separated by a distance of 10 mm (which is equivalent to 0.01 m). Since both objects have the same positive charge, they will exert a repulsive force on each other.
To calculate the magnitude of this repulsive force, we can use Coulomb's law formula:
F = (k * q1 * q2) / d^2
Where:
F is the magnitude of the electrical force between the two objects
k is the Coulomb constant (9 x 10^9 N·m^2/C^2)
q1 and q2 are the charges of the objects (+1 C in this case)
d is the distance between the objects (0.01 m in this case)
Plugging in the given values, we get:
F = (9 x 10^9 N·m^2/C^2 * 1 C * 1 C) / (0.01 m)^2
Simplifying the equation:
F = (9 x 10^9 N·m^2/C^2 * 1 C^2) / (0.0001 m^2)
F = 9 x 10^13 N
Based on this calculation, the magnitude of the repulsive force between the two objects is 9 x 10^13 N, which is a very strong force. Therefore, the answer is "repulsive, strong."