Write the equation of the graph in the form of y=mx+b that matches.
line j has a point at (0,8) and (3,0)
line k has points at (-5, -5) and (0,-3)
line l has points at (0,3) and (-7,0)
For line j:
Using the two given points, we can calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1)
x1 = 0, y1 = 8, x2 = 3, y2 = 0
m = (0 - 8) / (3 - 0) = -8 / 3
Now we can use the point-slope form of a linear equation: y - y1 = m(x - x1)
Plugging in the values: y - 8 = (-8/3)(x - 0)
Simplifying: y - 8 = (-8/3)x
Rearranging to slope-intercept form: y = (-8/3)x + 8
Therefore, the equation of line j is y = (-8/3)x + 8.
For line k:
Using the two given points, we can calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1)
x1 = -5, y1 = -5, x2 = 0, y2 = -3
m = (-3 - (-5)) / (0 - (-5)) = 2 / 5 = 2/5
Now we can use the point-slope form of a linear equation: y - y1 = m(x - x1)
Plugging in the values: y - (-5) = (2/5)(x - (-5))
Simplifying: y + 5 = (2/5)(x + 5)
Rearranging to slope-intercept form: y = (2/5)x + 5 - 5
Simplifying further: y = (2/5)x
Therefore, the equation of line k is y = (2/5)x.
For line l:
Using the two given points, we can calculate the slope (m) using the formula: m = (y2 - y1) / (x2 - x1)
x1 = 0, y1 = 3, x2 = -7, y2 = 0
m = (0 - 3) / (-7 - 0) = -3 / -7 = 3/7
Now we can use the point-slope form of a linear equation: y - y1 = m(x - x1)
Plugging in the values: y - 3 = (3/7)(x - 0)
Simplifying: y - 3 = (3/7)x
Rearranging to slope-intercept form: y = (3/7)x + 3
Therefore, the equation of line l is y = (3/7)x + 3.