Write the equation of the graph in the form of
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y=mx+b that matches. Click Here for Help Video.
Line J
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y=
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x +
Line K
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y=
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x+
Line L
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y=
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The equation of Line J is y = x + b.
The equation of Line K is y = -x + b.
The equation of Line L is y = x - b.
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Transform
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3
=
2
(
4
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+
2
)
y−3=2(4x+2) into slope-intercept form (
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+
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y=mx+b ). Click Here for Help Video
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y=
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To transform the equation y-3 = 2(4x+2) into slope-intercept form, we need to simplify and solve for y.
First, distribute 2 to (4x+2):
y-3 = 8x + 4
Next, isolate y by adding 3 to both sides of the equation:
y = 8x + 4 + 3
Simplifying further:
y = 8x + 7
So, the equation in slope-intercept form is y = 8x + 7.
Transform
3
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+
−
4
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−
8
3x+−4y=−8 into slope-intercept form (
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y=mx+b ). Click Here for Help Video
To transform the equation 3x + -4y = -8 into slope-intercept form, we need to simplify and solve for y.
First, rearrange the equation:
-4y = -3x - 8
Next, divide both sides of the equation by -4:
y = 3/4 x + 2
So, the equation in slope-intercept form is y = 3/4 x + 2.
Transform
−
6
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+
5
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=
−
5
−6x+5y=−5 into slope-intercept form (
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+
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y=mx+b ). Click Here for Help Video
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y=
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To transform the equation -6x + 5y = -5 into slope-intercept form, we need to simplify and solve for y.
First, rearrange the equation:
5y = 6x - 5
Next, divide both sides of the equation by 5:
y = (6/5)x - 1
So, the equation in slope-intercept form is y = (6/5)x - 1.
Write the equation of the graph in the form of
�
=
�
�
+
�
y=mx+b that matches. Click Here for Help Video.
Line J
�
=
y=
�
+
x +
Line K
�
=
y=
�
+
x+
Line L
�
=
y=
�
+
x+
I apologize for the confusion, but you haven't provided any information about the equations of Line J, Line K, or Line L. Please provide the equations for me to determine which equation matches the given form of y = mx + b.
To write the equation of the graph in the form of y=mx+b, we need to determine the values of m (the slope) and b (the y-intercept).
For Line J:
From the given equation, we can see that the slope, m, is equal to 1 because the coefficient of x is 1. The y-intercept, b, is equal to 0 because there is no constant term.
Therefore, the equation of Line J is y = 1x + 0, which simplifies to y = x.
For Line K:
From the given equation, we can see that the slope, m, is equal to 1 because the coefficient of x is 1. The y-intercept, b, is equal to 1 because there is a constant term of 1.
Therefore, the equation of Line K is y = 1x + 1, which simplifies to y = x + 1.
For Line L:
Unfortunately, the equation for Line L is not provided, so we cannot determine the values of m and b. Please provide the equation for Line L to further analyze it.