Rewrite the irrational cube rood ^3√48 as a product of an integer and another irrational cube root.
√48 can be simplified as √(16*3) = √16 * √3 = 4√3
Therefore, (√48)^3 = (4√3)^3 = 4^3 * (√3)^3 = 64 * √(3^3) = 64 * √27
So, (√48)^3 = 64√27
Therefore, (√48)^3 = (4√3)^3 = 4^3 * (√3)^3 = 64 * √(3^3) = 64 * √27
So, (√48)^3 = 64√27