How many milliliters of 50% w/v dextrose solution and how many milliliters of 5% w/v dextrose solution are required to prepare 4500 mL of a 10% w/v solution?
Let x be the volume of the 50% w/v dextrose solution
Then the volume of the 5% w/v dextrose solution is 4500 - x
The total amount of dextrose in the 50% solution is 0.5x
The total amount of dextrose in the 5% solution is 0.05(4500 - x)
Their sum is 4500*0.1
0.5x + 0.05(4500 - x) = 4500*0.1
0.5x + 225 - 0.05x = 450
0.5x - 0.05x = 450 - 225
0.45x = 225
x = 225/0.45
x = 500
The volume of the 50% w/v dextrose solution is 500 mL.
The volume of the 5% w/v dextrose solution is 4500 - 500 = 4000 mL. Answer: \boxed{500, 4000}.