How would you prepare 500 mL of 5% dextrose added to water from a 50% stock solution?
_________ mL 50% dextrose + ________mL water
You are reducing the concentration by a factor of 10, so you need to increase the volume by a factor of 10.
So, 50mL of 50%, filled to a volume of 500mL means you need to add 450mL of water.
Ah, preparing some sweet solutions, I see! To make 500 mL of 5% dextrose solution, we'll need to do a little math.
Now, if we have a 50% stock solution, that means it contains 50 grams of dextrose per 100 mL.
So, to find out how much of this stock solution we need, we can set up a proportion.
Let's call the amount of stock solution "x".
Since we know that the stock solution is 50% dextrose, we have:
50 grams/100 mL = x grams/500 mL
Cross-multiplying, we get:
100x = 50 * 500
Now, solving for x:
100x = 25,000
x = 250 mL
So, we'll need 250 mL of the 50% dextrose solution.
To find the amount of water needed, we subtract the stock solution volume from the total required volume:
500 mL - 250 mL = 250 mL
Therefore, you'll need to mix 250 mL of the 50% dextrose solution with 250 mL of water to prepare your 500 mL of 5% dextrose solution. Cheers!
To prepare 500 mL of 5% dextrose solution from a 50% stock solution, you will need to calculate the amount of stock solution and water to mix. Here's how you can do it:
Step 1: Determine the amount of dextrose needed:
The target solution is 5% dextrose, which means you need 5 g of dextrose in 100 mL of solution. Therefore, you will need 5% of 500 mL or 25 g of dextrose.
Step 2: Calculate the amount of stock solution:
Since the stock solution is 50% dextrose, you can set up the following equation to solve for x, the volume of the stock solution required:
(50%/100%) * x = 25 g
Simplifying the equation:
0.5 * x = 25 g
Solving for x:
x = 25 g / 0.5
x = 50 mL
So, you will need 50 mL of the 50% stock solution.
Step 3: Calculate the amount of water needed:
To determine the amount of water required, subtract the volume of the stock solution from the desired final volume:
500 mL - 50 mL = 450 mL
Therefore, you will need 50 mL of the 50% dextrose solution and 450 mL of water to prepare 500 mL of 5% dextrose solution.
To prepare 500 mL of 5% dextrose solution, we need to calculate the volumes of the 50% stock solution and water that need to be mixed.
Let's assume "x" mL of the 50% dextrose stock solution is needed. The volume of water required will be the remaining volume after adding the stock solution.
The equation would be:
x mL of 50% dextrose + (500 mL - x mL) of water = 500 mL of 5% dextrose solution.
To solve this equation for "x," we can use the fact that the concentration of the stock solution is 50% (or 0.5) and the desired concentration is 5% (or 0.05).
So we can set up the equation:
(0.5)(x mL) + (0 mL) = (0.05)(500 mL)
Simplifying the equation:
0.5x = 0.05 * 500
0.5x = 25
x = 25 / 0.5
x = 50 mL
Therefore, you would need to mix 50 mL of the 50% dextrose stock solution with 450 mL of water to prepare 500 mL of 5% dextrose solution.