(4d−3)+(12d+4)
To solve the expression (4d−3)+(12d+4), we need to combine like terms.
First, we distribute the positive sign to each term inside the parentheses:
4d - 3 + 12d + 4
Next, we can combine the terms with the variable (4d and 12d) and the constant terms (-3 and 4):
(4d + 12d) + (-3 + 4)
This simplifies to:
16d + 1
Therefore, (4d−3)+(12d+4) simplifies to 16d + 1.
12(x+4)+14(4x−2)
To solve the expression 12(x+4)+14(4x−2), we need to distribute the coefficients to each term inside the parentheses and then combine like terms.
First, we distribute 12 to each term inside the parentheses:
12(x) + 12(4) + 14(4x) - 14(2)
This simplifies to:
12x + 48 + 56x - 28
Next, we can combine the terms with the variable (12x and 56x) and the constant terms (48 and -28):
12x + 56x + 48 - 28
This simplifies to:
68x + 20
Therefore, 12(x+4)+14(4x−2) simplifies to 68x + 20.
sorry i put that in there wrong its
1/2(x+4)+1/4(4x−2)
No problem! To solve the expression 1/2(x+4)+1/4(4x−2), we need to distribute the coefficients and then combine like terms.
First, we distribute 1/2 to each term inside the first set of parentheses:
1/2 * x + 1/2 * 4
This simplifies to:
1/2x + 2
Next, we distribute 1/4 to each term inside the second set of parentheses:
1/4 * 4x + 1/4 * (-2)
This simplifies to:
1x + (-1/2)
Now we can combine the terms:
1/2x + 2 + 1x - 1/2
We can combine the terms with the variable (1/2x and 1x) and the constant terms (2 and -1/2):
(1/2x + 1x) + (2 - 1/2)
This simplifies to:
(3/2x) + (3/2)
Therefore, 1/2(x+4)+1/4(4x−2) simplifies to (3/2x) + (3/2).
don't simplifie the question
I apologize for simplifying the expression. To solve the expression 1/2(x+4)+1/4(4x−2) without simplifying, we can distribute the coefficients and rewrite the expression as follows:
1/2(x) + 1/2(4) + 1/4(4x) - 1/4(2)
This simplifies to:
1/2x + 2/2 + 1/4 * 4x - 1/4 * 2
Further simplifying, we have:
1/2x + 1 + 1x/4 - 1/2
Next, we can combine the terms with the variable (1/2x and 1x/4):
1/2x + 1x/4 + 1 - 1/2
To combine the fractions with different denominators, we need to find a common denominator:
The common denominator for 2, 4, and 2 is 4.
Thus, we can rewrite the expression as:
2/4x + 1/4x + 4/4 - 2/4
Combining the fractions, we have:
(2x + 1)/4x + 2/4
Since the numerators have a common factor of 1, we can simplify further:
(2x + 1)/4x + 1/2
Therefore, the expression 1/2(x+4)+1/4(4x−2) can be written as (2x + 1)/4x + 1/2 without simplification.
(2m−3)+(3n−1)+(3m+1)
To solve the expression (2m−3)+(3n−1)+(3m+1), we need to combine like terms.
First, we can add the terms with the variable m (2m and 3m):
2m + 3m = 5m
Next, we add the terms with the variable n (3n):
5m + 3n
Then, we add the constant terms (-3, -1, and 1):
-3 - 1 + 1 = -3
Finally, we combine the terms with the variables (5m and 3n) and the constant term (-3):
5m + 3n - 3
Therefore, (2m−3)+(3n−1)+(3m+1) simplifies to 5m + 3n - 3.
2(10b+4)−(b−2)
To solve the expression 2(10b+4)−(b−2), we need to distribute the coefficients and then combine like terms.
First, we distribute the coefficient 2 to each term inside the parentheses:
2 * 10b + 2 * 4 - (b - 2)
This simplifies to:
20b + 8 - (b - 2)
Next, we distribute the negative sign (-1) to each term inside the other parentheses:
20b + 8 - b + 2
This simplifies further to:
19b + 10
Therefore, 2(10b+4)−(b−2) simplifies to 19b + 10.
(3g−4)−2(3g+4)
To solve the expression (3g−4)−2(3g+4), we need to distribute the coefficient -2 to each term inside the parentheses and then combine like terms.
First, we distribute the coefficient -2 to each term inside the second set of parentheses:
(3g - 4) - 2*3g - 2*4
This simplifies to:
3g - 4 - 6g - 8
Next, we can combine the terms with the variable (-6g and 3g):
(3g - 6g) - 4 - 8
This simplifies further to:
-3g - 12
Therefore, (3g−4)−2(3g+4) simplifies to -3g - 12.
9(k+13)+10(12k−1) .(1 point)
Responses
14k+13
14 k plus 13
1912k−23
19 Start Fraction 1 over 2 End Fraction k minus Start Fraction 2 over 3 End Fraction
14k−23
14 k minus Start Fraction 2 over 3 End Fraction
14k−7
To solve the expression 9(k+13)+10(12k−1), we need to distribute the coefficients and then combine like terms.
First, we distribute 9 to each term inside the first set of parentheses:
9k + 9(13)
This simplifies to:
9k + 117
Next, we distribute 10 to each term inside the second set of parentheses:
10(12k) + 10(-1)
This simplifies to:
120k - 10
Now we can combine the terms:
9k + 117 + 120k - 10
We can combine the terms with the variable (9k and 120k) and the constant terms (117 and -10):
(9k + 120k) + (117 - 10)
This simplifies to:
129k + 107
Therefore, 9(k+13)+10(12k−1) simplifies to 129k + 107.
choose on of my answers please
Out of the provided answer choices, the correct answer is:
14k−7
4(g−2)+(g+2) .(1 point)
Responses
5g−6
5 g minus 6
5g+10
5 g plus 10
5g
5 g
5g−10
To solve the expression 4(g−2)+(g+2), we need to distribute the coefficients and then combine like terms.
First, we distribute 4 to each term inside the first set of parentheses:
4g - 4(2)
This simplifies to:
4g - 8
Next, we distribute 1 to each term inside the second set of parentheses:
g + 2
Now we can combine the terms:
4g - 8 + g + 2
We can combine the terms with the variable (4g and g) and the constant terms (-8 and 2):
4g + g - 8 + 2
This simplifies to:
5g - 6
Therefore, 4(g−2)+(g+2) simplifies to 5g - 6.
(h+k)−(2k−h) .(1 point)
Responses
2h−k
2 h minus k
2h+k
2 h plus k
−k
negative k
−2h−k
To solve the expression (h+k)−(2k−h), we need to distribute the negative sign to each term inside the second set of parentheses and then combine like terms.
First, we distribute the negative sign to each term inside the second set of parentheses:
(h + k) - 2k + h
Now we can combine the terms:
h + k - 2k + h
We can combine the terms with the variable (h and h) and the constant terms (k and -2k):
2h + k - 2k
Now we combine the like terms:
2h - k
Therefore, (h+k)−(2k−h) simplifies to 2h - k.
(p−3)−(2.4+2p) .(1 point)
Responses
p−5.4
p minus 5.4
−p−5.4
negative p minus 5.4
3p−5.4
3 p minus 5.4
−p+5.4
To solve the expression (p−3)−(2.4+2p), we need to distribute the negative sign to each term inside the second set of parentheses and then combine like terms.
First, we distribute the negative sign to each term inside the second set of parentheses:
(p - 3) - 2.4 - 2p
Now we can combine the terms:
p - 3 - 2.4 - 2p
Next, we combine the terms with the variable (p and -2p) and the constant terms (-3 and -2.4):
(p - 2p) - 3 - 2.4
This simplifies to:
-p - 3 - 2.4
Combining the constant terms, we have:
-p - 5.4
Therefore, (p−3)−(2.4+2p) simplifies to -p - 5.4.