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Use the Remainder Theorem to find the remainder when P(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3
To find the remainder when P(x) is divided by x+3 using the Remainder Theorem, we substitute -3 into P(x).
P(-3) = (-3)^4 - 9(-3)^3 - 5(-3)^2 - 3(-3) + 4
= 81 - 9(-27) - 5(9) + 9 + 4
= 81 + 243 - 45 + 13
= 292
Therefore, the remainder is 292 when P(x) is divided by x+3.