Given that f(x) = 9x^2 -50, apply the remainder theorem to find the remainder of (9x^2 - 50) divided by (x - 7/3)
To apply the remainder theorem, we need to find f(7/3) since the divisor is x - 7/3.
We substitute x = 7/3 into f(x) = 9x^2 - 50:
f(7/3) = 9(7/3)^2 - 50
= 9(49/9) - 50
= 49 - 50
= -1
So, the remainder is -1.
To apply the remainder theorem, we need to evaluate the polynomial function f(x) at x = 7/3.
Substitute x = 7/3 into the polynomial f(x):
f(7/3) = 9(7/3)^2 - 50
Simplify the expression:
f(7/3) = 9(49/9) - 50
f(7/3) = 49 - 50
f(7/3) = -1
Therefore, the remainder when (9x^2 - 50) is divided by (x - 7/3) is -1.
To apply the remainder theorem, first, we need to understand the theorem itself. The remainder theorem states that if a polynomial f(x) is divided by a linear factor (x - a), then the remainder is equivalent to f(a).
In this case, we are given that f(x) = 9x^2 - 50 and we want to divide it by (x - 7/3).
To find the remainder, we need to substitute the value of x = 7/3 into the polynomial. So, let's substitute x = 7/3 into f(x):
f(7/3) = 9(7/3)^2 - 50
Now, simplify the expression:
f(7/3) = 9(49/9) - 50
f(7/3) = 49 - 50
f(7/3) = -1
Therefore, the remainder when (9x^2 - 50) is divided by (x - 7/3) is -1.