p(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3 use the remainder theorem to find the remainder show all your work
To find the remainder when dividing p(x) by x + 3 using the Remainder Theorem, we substitute -3 for x in the polynomial p(x) and perform the calculations.
p(-3) = (-3)^4 - 9(-3)^3 - 5(-3)^2 - 3(-3) + 4
= 81 - 9(-27) - 5(9) + 9 + 4
= 81 + 243 - 45 + 9 + 4
= 292
Hence, the remainder when p(x) is divided by x + 3 is 292.