for which equation is the order of steps to first divide both sides by 2 and then add 10 to both sides
The equation for the order of steps to first divide both sides by 2 and then add 10 to both sides is as follows:
2x - 4 = 6
The order of steps you described, dividing both sides by 2 and then adding 10 to both sides, can be applied to any algebraic equation. Let's consider a general equation where this order of steps can be used.
Let's say we have the equation:
ax + b = c
To solve this equation using the given order of steps, we would follow these steps:
Step 1: Divide both sides by 2:
(ax + b)/2 = c/2
Step 2: Add 10 to both sides:
(ax + b)/2 + 10 = c/2 + 10
So, this order of steps can be applied to any equation of the form ax + b = c.
To identify the equation where the order of steps involves dividing both sides by 2 first, and then adding 10 to both sides, we need to consider an equation with variables and constants.
Let's create a generic equation:
ax + b = c
To follow the desired order of steps, we divide both sides of the equation by 2 first:
(ax + b)/2 = c/2
This gives us:
(1/2)(ax + b) = c/2
Now, we want to add 10 to both sides:
(1/2)(ax + b) + 10 = c/2 + 10
Now, let's simplify the equation further:
(1/2)(ax + b) + 10 = (c + 10)/2
So, for the given desired order of steps, any equation in the form (1/2)(ax + b) + 10 = (c + 10)/2 would fulfill the condition.