For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
A.8(x − 6) = 48
B.6x − 8 = 48
C.6(x + 8) = 48
D. 6(x − 8) = 48
C.6(x + 8) = 48
The equation for which the order of steps is to first divide both sides by 6 and then add 8 to both sides is:
C. 6(x + 8) = 48
To determine which equation requires dividing both sides by 6 first and then adding 8 to both sides, we need to analyze each equation.
A. 8(x − 6) = 48
To solve this equation, we start by distributing the 8 to the terms inside the parentheses:
8x - 48 = 48
Next, we can add 48 to both sides to isolate the variable:
8x = 96
Finally, divide both sides by 8 to solve for x:
x = 12
B. 6x − 8 = 48
For this equation, we want to add 8 to both sides first, so we have:
6x = 56
Then, we divide both sides by 6:
x = 9.333 (or approximately 9.33)
C. 6(x + 8) = 48
We can simplify this equation by distributing the 6 to the terms inside the parentheses:
6x + 48 = 48
Next, we subtract 48 from both sides:
6x = 0
Finally, we divide both sides by 6:
x = 0
D. 6(x − 8) = 48
To solve this equation, we begin by distributing the 6 to the terms inside the parentheses:
6x - 48 = 48
Then, we add 48 to both sides:
6x = 96
Finally, we divide both sides by 6:
x = 16
After analyzing each equation, we find that the equation that requires dividing both sides by 6 first and then adding 8 to both sides is option B, given by:
B. 6x − 8 = 48