For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
8(x-6)=48
6(x-8)=48
6(x+8)=48
6x-8=48
The equation for which the order of steps to first divide both sides by 6 and then add 8 to both sides is relevant is:
6(x-8)=48
The equation for which the order of steps to first divide both sides by 6 and then to add 8 to both sides is 6(x-8)=48.
To determine the equation that requires dividing both sides by 6 first and then adding 8 to both sides, we need to follow a specific order of steps.
Let's go through the options and see which equation matches the required order:
1. 8(x-6) = 48: In this equation, we have to apply the distributive property first, distributing the 8 into (x-6). This gives us 8x - 48 = 48. Here, we didn't divide both sides by 6 before adding 8, so this equation does not match the required order.
2. 6(x-8) = 48: In this equation, we again have to apply the distributive property first, distributing the 6 into (x-8). This gives us 6x - 48 = 48. Here, we didn't divide both sides by 6 before adding 8, so this equation does not match the required order.
3. 6(x+8) = 48: In this equation, we can directly divide both sides by 6 to eliminate the coefficient of 6 on the left side. After dividing, we get x + 8 = 8. Now, to complete the required order of steps, we need to subtract 8 from both sides, which gives us x = 0. Therefore, this equation does not match the required order either.
4. 6x-8 = 48: In this equation, we can directly add 8 to both sides to eliminate the constant term -8 on the left side. After adding, we get 6x = 56. Now, to complete the required order of steps, we need to divide both sides by 6, which gives us x = 56/6 which simplifies to x = 9.33 (rounded to two decimal places).
So, the equation that matches the required order of steps to first divide both sides by 6 and then add 8 to both sides is 6x-8 = 48.