for which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point) Responses 6(x + 8) = 48 6 left parenthesis x plus 8 right parenthesis equals 48 6(x − 8) = 48 6 left parenthesis x minus 8 right parenthesis equals 48 6x − 8 = 48 6 x minus 8 equals 48 8(x − 6) = 48 8 left parenthesis x minus 6 right parenthesis equals 48
The equation for which the order of steps is to first divide both sides by 6 and then to add 8 to both sides is:
6(x - 8) = 48
The equation for which the order of steps is to first divide both sides by 6 and then add 8 to both sides is:
6x − 8 = 48
To find the equation for which the order of steps is first dividing both sides by 6, and then adding 8 to both sides, we need to look for an equation where these steps have been applied in that specific order.
Let's analyze each option:
1) 6(x + 8) = 48
This equation has a multiplication step before adding 8 to both sides, so it doesn't match the required order of steps.
2) 6(x - 8) = 48
Similar to the first option, this equation requires a multiplication step before adding 8 to both sides, so it doesn't match the required order of steps.
3) 6x - 8 = 48
In this equation, we already have the division step completed (dividing both sides by 6) and then subtracting 8 to both sides. So this equation matches the required order of steps.
4) 8(x - 6) = 48
Similar to the first two options, this equation requires a multiplication step before adding 8 to both sides, so it doesn't match the required order of steps.
Therefore, option 3) 6x - 8 = 48 is the equation for which the order of steps is first dividing both sides by 6, and then adding 8 to both sides.