Rewrite the irrational cube root 48−−√3 as a product of an integer and another irrational cube root.(1 point)
Responses
412−−√3
4 root index 3 start root 12 end root
26–√3
2 root index 3 start root 6 end root
−26–√3
negative 2 root index 3 start root 6 end root
43–√3
4∛3
To rewrite the irrational cube root of 48 as a product of an integer and another irrational cube root, we need to factorize 48 and look for perfect cube factors.
The prime factorization of 48 is 2^4 * 3^1.
Now, let's find a perfect cube factor of 48. The largest perfect cube factor of 48 is 8, which is 2^3.
We can rewrite 48 as (2^3) * 6.
Taking the cube root of 48, we can split it as the product of the cube root of (2^3) multiplied by the cube root of 6.
Therefore, the irrational cube root of 48 can be rewritten as 2∛6.