The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2×106 years? Write the answer in scientific notation, expressed to the exact decimal place.(1 point)
To find how many meters the tectonic plate would move in 2x10^6 years, we can multiply the rate of movement (0.006 m/year) by the number of years.
0.006 m/year * 2x10^6 years = 12x10^3 meters
12x10^3 meters can be written in scientific notation as 1.2x10^4 meters.
To find out how many meters the tectonic plate would move in 2x10^6 years, we can multiply the rate of movement (0.006 m/year) by the number of years (2x10^6):
0.006 m/year * 2x10^6 years
To multiply these two numbers, we can first multiply the coefficients (0.006 * 2 = 0.012), and then add the exponents (10^6):
0.012 * 10^6
This can be expressed in scientific notation as: 1.2x10^4 meters.
To find out how many meters the tectonic plate would move in 2×10^6 years, you need to multiply the rate at which it moves per year (0.006 m) by the number of years (2×10^6).
To do this, multiply the two numbers:
0.006 m/year * 2×10^6 years
To multiply 0.006 by 2, you get 0.012.
To multiply 10^6 by 10^6, you add the exponents together: 10^6 + 10^6 = 10^12.
So, the tectonic plate would move 0.012 meters in 2×10^6 years.
Expressing this in scientific notation:
0.012 m = 1.2 × 10^-2 m
Therefore, the tectonic plate would move 1.2 × 10^-2 meters in 2×10^6 years.