The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2 10 years?
To find the distance the tectonic plate would move in 2 10 years, you can multiply the average velocity by the number of years.
0.006 m per year * 10 years = <<0.006*10=0.06>>0.06 m
Therefore, the tectonic plate would move 0.06 meters in 2 10 years.
To find out how many meters the average tectonic plate would move in 20 years at the rate of 0.006 m per year, you can simply multiply the rate of movement by the number of years.
0.006 m/year * 20 years = 0.12 m
Therefore, the average tectonic plate would move approximately 0.12 meters in 20 years.
To calculate the distance a tectonic plate would move in 20 years, we need to multiply the rate of movement per year by the number of years.
Given:
Rate of movement per year = 0.006 m/year
Number of years = 20
To calculate the distance, we use the formula:
Distance = Rate of movement per year × Number of years
Plugging in the values:
Distance = 0.006 m/year × 20 years
Calculating this expression:
Distance = 0.12 m
Therefore, a tectonic plate would move approximately 0.12 meters in 20 years.