The average tectonic plate moves at the rate of 0 000 m per year How many meters would it move in 2 x 10 years? Write the answer in scientific notation, expressed to the exact decimal place (1 point)
To find the distance a tectonic plate would move in 2 x 10 years, we can multiply the average rate of movement (0.000 m/year) by the number of years (2 x 10 years).
0.000 m/year x 2 x 10 years = 0.000 x 20 = 0.00 m
The distance the tectonic plate would move in 2 x 10 years would be 0.00 meters.
In scientific notation, this can be expressed as 0.00 x 10^0 meters.
The average tectonic plate moves at a rate of 0.000 meters per year.
To find out how many meters it would move in 2 x 10 years, we can multiply the speed by the number of years:
0.000 meters/year x (2 x 10 years) = 0.000 meters/year x 20 years
= 0.000 meters/year x 20 years = 0.000 meters/year x 2 x 10 years
= 0.000 meters/year x 20 years = 0.000 x 10 meters
= 0.00 meters/year
Therefore, in 2 x 10 years, the tectonic plate would move 0.00 meters.
In scientific notation, this can be written as 0.00 x 10^0 meters (since anything multiplied by 10^0 remains unchanged).
Therefore, the answer in scientific notation, expressed to the exact decimal place, is 0.00 x 10^0 meters.
To calculate the total distance the tectonic plate would move in 2 x 10 years, we need to multiply the average rate of movement by the number of years.
The average rate of movement is given as 0.000 m per year.
We can express 2 x 10 years as 20 years.
To calculate the total distance, we multiply the rate by the number of years:
0.000 m/year * 20 years = 0.000 * 20 m
Multiplying these numbers, we get:
0.000 * 20 = 0 m
Therefore, the tectonic plate would move 0 meters in 2 x 10 years.
Since the distance is 0, we can write the answer in scientific notation as 0.0 x 10^0 meters.