The average human heart beats about 3.5×107 times per year. The current population of Massachusetts is about 7×106 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place
To calculate the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per person by the current population of Massachusetts.
Heartbeats in Massachusetts per year = (Average heartbeats per person) x (Population of Massachusetts)
= (3.5×10^7 beats/year) x (7×10^6 people)
To multiply these two numbers, we add the exponents and multiply the coefficients:
= (3.5 x 7) × (10^7 x 10^6) beats/year
= 24.5 × 10^13 beats/year
The answer, expressed in scientific notation to the exact decimal place, is 2.45 × 10^14 beats/year.
To find the total number of heartbeats occurring in Massachusetts per year, we need to multiply the average number of heartbeats per year by the current population of Massachusetts:
3.5×10^7 heartbeats/year * 7×10^6 people = (3.5 * 7) × (10^7 * 10^6) heartbeats/year
= 24.5 × (10^7 * 10^6) heartbeats/year
= 24.5 × (10^(7+6)) heartbeats/year
= 24.5 × 10^13 heartbeats/year
Expressing the answer in scientific notation, the estimated number of heartbeats occurring in Massachusetts per year is approximately 2.45×10^14 heartbeats/year.
To find the number of heartbeats that occur in Massachusetts per year, we need to multiply the average number of heartbeats per person by the current population of Massachusetts.
The average number of heartbeats per person per year is given as 3.5×10^7.
The current population of Massachusetts is about 7×10^6 people.
To find the total number of heartbeats, we can multiply these two values:
(3.5×10^7) * (7×10^6) = (3.5 * 7) * (10^7 * 10^6) = 24.5 * 10^13
Therefore, the number of heartbeats that occur in Massachusetts per year is 2.45×10^14.