The average human heart beats about 3.5 ×10^7 times per year. The current population of Massachusetts is about 7×10^6 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per person by the current population of Massachusetts.
Average number of heartbeats per person per year = 3.5 × 10^7
Current population of Massachusetts = 7 × 10^6
Total number of heartbeats in Massachusetts per year = (3.5 × 10^7) * (7 × 10^6)
= 24.5 × 10^13
Written in scientific notation, the answer is 2.45 × 10^14.
To find the total number of heartbeats that occur in Massachusetts per year, we can multiply the average number of heartbeats per person by the population of Massachusetts.
Average number of heartbeats per person per year = 3.5 × 10^7
Population of Massachusetts = 7 × 10^6
Total number of heartbeats in Massachusetts per year = (3.5 × 10^7) × (7 × 10^6)
Using the laws of exponents, we can simplify the expression:
Total number of heartbeats in Massachusetts per year = (3.5 × 7) × (10^7 × 10^6)
Total number of heartbeats in Massachusetts per year = 24.5 × 10^(7+6)
Since 24.5 is not in scientific notation, we can rewrite it as 2.45 × 10^1 (moving the decimal one place to the left).
Total number of heartbeats in Massachusetts per year = 2.45 × 10^1 × 10^(7+6)
Total number of heartbeats in Massachusetts per year = 2.45 × 10^(1+13)
Adding the exponents, we get:
Total number of heartbeats in Massachusetts per year = 2.45 × 10^14
Therefore, there are approximately 2.45 × 10^14 heartbeats that occur in Massachusetts per year.
To find the total number of heartbeats that occur in Massachusetts per year, we can multiply the average number of heartbeats per person by the population of Massachusetts.
Average number of heartbeats per person per year = 3.5 × 10^7
Population of Massachusetts = 7 × 10^6
To calculate the total number of heartbeats in Massachusetts per year, we multiply these two numbers together:
Total heartbeats = (3.5 × 10^7) * (7 × 10^6)
When multiplying numbers in scientific notation, we can add the exponents and multiply the coefficients:
Total heartbeats = (3.5 * 7) × 10^(7 + 6)
Simplifying the multiplication of the coefficients:
Total heartbeats = 24.5 × 10^13
Writing the answer in scientific notation, we have:
Total heartbeats = 2.45 × 10^14
Therefore, about 2.45 × 10^14 heartbeats occur in Massachusetts per year.