The average human heart beats about 3.5×107 times per year. The current population of Massachusetts is about 7×106 people. About how many heartbeats occur in Massachusetts per year? Write the answer in scientific notation. Express the answer to the exact decimal place.(1 point)
$$
To find the total number of heartbeats in Massachusetts per year, we can multiply the average heartbeats per person per year by the population of Massachusetts:
3.5 × 10^7 beats/person/year × 7 × 10^6 people = (3.5 × 7) × (10^7 × 10^6) beats/year = 24.5 × 10^13 beats/year.
This can be expressed in scientific notation as 2.45 × 10^14 beats/year.
To find the total number of heartbeats in Massachusetts per year, we can multiply the average number of heartbeats per year by the current population of Massachusetts.
The average number of heartbeats per year is given as 3.5 x 10^7.
The current population of Massachusetts is 7 x 10^6.
Therefore, the total number of heartbeats in Massachusetts per year is:
3.5 x 10^7 * 7 x 10^6
To multiply two numbers in scientific notation, we multiply the coefficients and add the exponents:
(3.5 * 7) x (10^7 * 10^6)
= 24.5 x 10^(7+6)
= 24.5 x 10^13
Therefore, the total number of heartbeats in Massachusetts per year is 2.45 x 10^14.
To find the number of heartbeats that occur in Massachusetts per year, we can multiply the average number of heartbeats per person per year by the population of Massachusetts.
First, let's convert the average number of heartbeats per person per year to scientific notation:
3.5 × 10^7
Next, let's multiply this by the population of Massachusetts:
3.5 × 10^7 * 7 × 10^6
To multiply numbers in scientific notation, we can multiply the coefficients (3.5 * 7) and add the exponents (7 + 6):
(3.5 * 7) × 10^(7 + 6)
The product of 3.5 and 7 is 24.5, and the exponent is 13:
24.5 × 10^13
Therefore, the number of heartbeats that occur in Massachusetts per year is approximately 2.45 × 10^14.