Your class hope to collect at least 325 cans of food for the annual food drive. There were 135 cans donated the first week and 89 more the second week. Write and inequality that describe the situation let's see represent the number of cancer food that must be collected by the end of the third week of your class to meet or surpass its goal. How many cans are needed to meet or surpass the goal? In every detail break down
Let's start by representing the number of cans collected in the first week as "C1" and the number of cans collected in the second week as "C2". We know that C1 = 135 and C2 = 89.
To represent the number of cans that must be collected by the end of the third week to meet or surpass the goal, let's use the variable "C3".
Since the goal is to collect at least 325 cans, we can write the following inequality:
C1 + C2 + C3 ≥ 325
Now, let's substitute the known values:
135 + 89 + C3 ≥ 325
Simplifying the equation, we have:
224 + C3 ≥ 325
To find the amount of cans needed to meet or surpass the goal, we subtract 224 from both sides of the inequality:
C3 ≥ 101
Therefore, the class needs to collect at least 101 more cans to meet or surpass the goal.
In conclusion, the inequality that represents the situation is C3 ≥ 101. The class needs to collect at least 101 more cans to meet or surpass the goal.
Let's start by breaking down the information provided:
- The goal is to collect at least 325 cans of food.
- In the first week, 135 cans were donated.
- In the second week, 89 more cans were donated.
To represent the number of cans of food that must be collected by the end of the third week to meet or surpass the goal, we can use the following inequality:
135 + 89 + x ≥ 325
In this inequality, x represents the number of cans that need to be collected in the third week.
To find out how many cans are needed to meet or surpass the goal, we can solve this inequality:
135 + 89 + x ≥ 325
Simplifying the equation, we have:
224 + x ≥ 325
Subtracting 224 from both sides of the equation, we get:
x ≥ 325 - 224
x ≥ 101
Therefore, to meet or surpass the goal, the class needs to collect at least 101 cans of food in the third week.
To write an inequality that represents the situation, we need to consider the number of cans donated in each week.
Let's denote the number of cans collected in the first week as "w1" and the number of cans collected in the second week as "w2". We are given that w1 = 135 and w2 = 89.
Now, let's represent the number of cans collected in the third week as "w3".
To meet or surpass the goal of collecting at least 325 cans of food, the total number of cans collected from all three weeks must be greater than or equal to 325. We can express this as:
w1 + w2 + w3 ≥ 325
Substituting the known values, we have:
135 + 89 + w3 ≥ 325
Adding the known values, we have:
224 + w3 ≥ 325
Finally, we can subtract 224 from both sides of the inequality to isolate the variable:
w3 ≥ 325 - 224
Simplifying further, we find:
w3 ≥ 101
Therefore, an inequality that describes the situation is w3 ≥ 101.
To determine the number of cans needed to meet or surpass the goal, we can use the minimum value for w3, which is 101. So, at least 101 cans need to be collected in the third week to meet or surpass the goal of 325 cans.