A competitive cliff diver jumps frome heights of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t = 2 by using the formula 75-16t², where t is time in seconds
To find the number of feet the diver is above the ocean in 2 seconds, we substitute t=2 into the formula 75-16t².
So, we have 75-16(2)².
Simplifying, we get 75-16(4).
Further simplifying, we get 75-64.
Therefore, the number of feet the diver is above the ocean in 2 seconds is 11 feet.
To find the number of feet the diver is above the ocean in 2 seconds, we need to evaluate the expression 75 - 16t² for t = 2.
Plugging in t = 2 into the expression, we get:
75 - 16(2)²
Now, let's simplify the expression:
75 - 16(4)
75 - 64
Finally, subtracting the two numbers gives us the answer:
11 feet.
Therefore, the diver is 11 feet above the ocean after 2 seconds.
To find the number of feet the diver is above the ocean in 2 seconds, we can use the formula 75 - 16t^2, where t is the time in seconds.
First, substitute t = 2 into the formula:
75 - 16(2^2)
Next, simplify the expression inside the parentheses:
75 - 16(4)
Multiply 16 by 4:
75 - 64
Subtract 64 from 75:
11
Therefore, the diver is 11 feet above the ocean at 2 seconds.