A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t = 2 by using the formula 75 - 16t^2, where t is time in seconds
To find the number of feet the diver is above the ocean in 2 seconds, evaluate the formula 75 - 16t^2 for t = 2.
Plugging t = 2 into the formula, we get:
75 - 16(2)^2
75 - 16(4)
75 - 64
11
Therefore, the diver is 11 feet above the ocean in 2 seconds.