A competitive cliff diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2 by using the formula 75-16t2 where t is time in seconds
To find the number of feet the diver is above the ocean in 2 seconds, we can evaluate the formula 75 - 16t^2 at t = 2.
Substituting t = 2 into the formula, we have:
75 - 16(2^2) = 75 - 16(4) = 75 - 64 = 11.
Therefore, the diver is 11 feet above the ocean in 2 seconds.