Rewrite the irrational cube root ^3√48 as a product of an integer and another irrational cube root.(1 point)
Responses
2^3√6
2 root index 3 start root 6 end root
−2^3√6–
negative 2 root index 3 start root 6 end root
4^3√12
4 root index 3 start root 12 end root
4^3√3
4 root index 3 start root 3 end root
4 root index 3 start root 3 end root
To rewrite the irrational cube root ^3√48 as a product of an integer and another irrational cube root, we can start by factoring 48.
The prime factorization of 48 is 2^4 * 3.
Now, we need to identify a perfect cube in the prime factors. In this case, 2 is a perfect cube, since 2^3 = 8.
Next, we can express 48 as a product of 2^3 and another factor: 48 = (2^3) * 6.
Therefore, we can rewrite ^3√48 as 2^3√6. So the answer is 2^3√6.