Subtract 12(z+4)−3(14z+1) . Use fractions in final form.(1 point)
To solve this expression, we distribute the numbers outside the parentheses to the numbers inside.
12(z+4) becomes 12z + 48.
-3(14z + 1) becomes -42z - 3.
Now we can combine like terms by subtracting the second expression from the first:
(12z + 48) - (-42z - 3)
= 12z + 48 + 42z + 3
= 54z + 51
So, the final answer is 54z + 51.
To subtract 12(z+4) - 3(14z+1), we can first simplify the expression inside the parentheses.
12(z+4) simplifies to 12z + 48, and 3(14z+1) simplifies to 42z + 3.
Now we can substitute these simplified expressions back into the original equation:
12z + 48 - (42z + 3).
To subtract these two expressions, we distribute the negative sign (-) to both terms within the parentheses:
12z + 48 - 42z - 3.
Next, we collect like terms:
(12z - 42z) + (48 - 3).
Simplifying further:
-30z + 45.
So, the final answer, in fraction form, is:
-30z + 45.
To subtract the given expressions, we need to distribute the coefficients to the terms within the parentheses and then combine like terms.
First, let's distribute the coefficients:
12(z+4) = 12z + 48
3(14z+1) = 42z + 3
Now, let's subtract the two expressions:
12z + 48 - (42z + 3)
To simplify further, we need to combine like terms:
(12z - 42z) + (48 - 3)
Combining like terms:
-30z + 45
Now, let's express the answer using fractions. To do this, we divide the result by a common factor, if possible. In this case, the common factor is 15.
Dividing both terms by 15 to express the answer in fractions:
(-30z/15) + (45/15)
Simplifying the fractions:
-2z/1 + 3/1
Finally, we can write the answer in the final form using fractions:
-2z + 3