You and your three friends are going to the State Fair. It costs $5 per person for admission into the fair and $3 for each ride. Which algebraic expression represents the TOTAL amount of money it will cost for you and your three friends to get into the fair and ride "x" amount of rides? (2 points)Responses

15x
3x + 5
5x + 3
3x + 20

The algebraic expression that represents the TOTAL amount of money it will cost for you and your three friends to get into the fair and ride "x" amount of rides is:

3x + 20

At the fair there are two bean bag toss games. You gain 3/4 of a point for each bean bag that you get on the target and you lose 1/2 point for each bean bag that does not land on the target. Your total amount of points for this game can be represented by 3/4h - 1/2g. In a different bean bag toss game you gain 7/8 points for each bean bag that get on the target and you lose 3/4 points for each bean bag that does not land on the target. Your total amount of points for this game can be represented by 7/8h - 3/4g. You can figure out the total number of points earned by simplifying this expression: (3/4h - 1/2g) + (7/8h - 3/4g). What would this expression be simplified? (Hint: Combine like terms!) (2 points)Responses

10/14h - 4/6g
15/8h + 5/4g
1 5/8h - 1 1/4g
1/2h - 1 3/4g

To simplify the expression (3/4h - 1/2g) + (7/8h - 3/4g), we combine like terms by adding the coefficients of h and g:

(3/4h + 7/8h) + (-1/2g - 3/4g)

To add the fractions, we need a common denominator. The least common multiple of 4 and 8 is 8, so we can rewrite the expression as:

(6/8h + 7/8h) + (-4/8g - 6/8g)

Combining the fractions:

(13/8h) + (-10/8g)

Simplifying the expression:

13/8h - 10/8g

We can further simplify by dividing both the numerator and denominator by 2:

(13/8h) - (10/8g) = (13/8)h - (10/8)g = (13h - 10g)/8

Therefore, the simplified expression is 13h - 10g/8, which can also be written as 1 5/8h - 1 1/4g.

Complete this fill-in-the-blank problem. (4 points)

When you evaluate an expression, you substitute a number in for a _________ For example, to evaluate the expression 4y+3 for y=6, you would substitute 6 for "y". You would then solve using the Order of Operations. So, 4(6)+3= _______ You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k+5)+(3k-7). You would add together the coefficients (numbers) in front of "k" and add together the constants or numbers. Adding or subtracting the same variables together is called combining ________ So, you would combine 6k + 3k which would equal 9k and you would combine the constants, 5 + -7 which would equal _____
Can you make the missing words in bold

When you evaluate an expression, you substitute a number in for a variable. For example, to evaluate the expression 4y+3 for y=6, you would substitute 6 for "y". You would then solve using the Order of Operations. So, 4(6)+3= 27. You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k+5)+(3k-7). You would add together the coefficients (numbers) in front of "k" and add together the constants or numbers. Adding or subtracting the same variables together is called combining like terms. So, you would combine 6k + 3k which would equal 9k and you would combine the constants, 5 + -7 which would equal -2.

can you put the missing words in bold please

When you evaluate an expression, you substitute a number in for a variable. For example, to evaluate the expression 4y+3 for y=6, you would substitute 6 for "y". You would then solve using the Order of Operations. So, 4(6)+3= 27. You can also simplify algebraic expressions without knowing what the variables equal. For example, in this expression, (6k+5)+(3k-7). You would add together the coefficients (numbers) in front of "k" and add together the constants or numbers. Adding or subtracting the same variables together is called combining like terms. So, you would combine 6k + 3k which would equal 9k and you would combine the constants, 5 + -7 which would equal -2.

At the State Fair you buy 4 combo meals for you and your three friends. Each meal comes with 3 chicken tenders and 2 fried Oreos. How many chicken tenders and fried Oreos do you buy all together? How could you set up and solve this problem using the Distributive Property? (3 points)

To find the total number of chicken tenders and fried Oreos bought all together, we can multiply the number of combo meals by the number of chicken tenders and fried Oreos in each meal.

In this case, for each combo meal, we have 3 chicken tenders and 2 fried Oreos.

Using the Distributive Property, we can set up the problem as follows:

Total number of chicken tenders = (Number of combo meals) * (Number of chicken tenders in each meal)
= 4 * 3
= 12

Total number of fried Oreos = (Number of combo meals) * (Number of fried Oreos in each meal)
= 4 * 2
= 8

Therefore, all together, you would buy 12 chicken tenders and 8 fried Oreos.

can you make it a bit more simplified and make it look like i didnt plagiarize it