You are going to the fair with your friends. Tickets to enter the fair are $7 and each ride (x)
costs an additional $0.50. You can spend no more than the $20 you have in your pocket. Which
inequality would most accurately model your situation?
Let x represent the number of rides. The cost of the tickets and the rides can be represented by the inequality:
7 + 0.50x ≤ 20
The inequality that would accurately model the situation is:
7 + 0.50x ≤ 20
This inequality represents the fact that you have to pay $7 for the ticket to enter the fair, and for each ride (x) you want to go on, you would need to pay an additional $0.50. The sum of these amounts cannot exceed the $20 you have in your pocket.
To find the inequality that accurately represents your situation, we need to consider the total cost you can afford, including both the ticket price and the cost for each ride.
Let's break it down:
The ticket price is a fixed cost of $7.
The cost for each ride is an additional $0.50 per ride, denoted by the variable 'x'. So, if you go on 'x' rides, the additional cost would be 0.50x.
To find the total cost, we add the ticket price and the additional ride cost:
Total cost = Ticket price + Additional ride cost = $7 + 0.50x
However, you cannot spend more than the $20 you have in your pocket. So the total cost should be less than or equal to $20.
Therefore, the inequality that most accurately models your situation is:
$7 + 0.50x ≤ $20
or written in a simplified form:
0.50x ≤ $20 - $7
0.50x ≤ $13