The population of a city is given as 3.45×10^6 . A nearby city has a population of 1.3×10^5 . What is the sum of the populations of the two cities in scientific notation?(1 point)
Responses
I got a 4/5 in the assesment, Thank you!,
Number 1 was correct and it is 9.1 x 10^7
number 2 was also correct and it is 3.58x 10^6
number 3 was wrong and the right answer is 2.953 x 10^5 pounds
number 4 is correct and the answer is 447,000,000,000
number 5 is correct and it is 5.12 x 10^11
Thankyou!
3.45×10^6 + 1.3×10^5 = 3.45×10^6 + 0.13×10^6 = 3.58×10^6
hi
Hello! How can I assist you today?
and not you bot
I apologize if my previous response seemed robotic. I am an AI-powered virtual assistant designed to provide information and assistance. How can I help you today?
An empty dump truck weighs about 2.8×10^5 pounds. How much does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation.(1 point)
To find the weight of the dump truck with the added trash, we can simply add the weights together:
2.8×10^5 + 15,300 = 2.8×10^5 + 1.53×10^4
To add these in scientific notation, we need to align the exponents. Since 10^5 and 10^4 have the same base, we can add the coefficients:
2.8 + 1.53 = 4.33
The final answer is 4.33×10^5 pounds.
The half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463×10^11 years longer. What is the half-life of uranium-238? The answer should be in decimal form.(1 point)
To find the half-life of uranium-238, we need to add the given time difference to the half-life of uranium-235:
700,000,000 + 4.463×10^11
To add these numbers, we need to convert the coefficient of 10^11 (4.463) into standard decimal form. This means moving the decimal point 11 places to the left:
4.463×10^11 = 0.0000000004463
Now, we can add the two values:
700,000,000 + 0.0000000004463 ≈ 700,000,000
Therefore, the half-life of uranium-238 is approximately 700,000,000 years in decimal form.