The population of a city is given as 3.45×10^6 . A nearby city has a population of 1.3×10^5 . What is the sum of the populations of the two cities in scientific notation?(1 point)
Responses
I got a 4/5 in the assesment, Thank you!,
Number 1 was correct and it is 9.1 x 10^7
number 2 was also correct and it is 3.58x 10^6
number 3 was wrong and the right answer is 2.953 x 10^5 pounds
number 4 is correct and the answer is 447,000,000,000
number 5 is correct and it is 5.12 x 10^11
Thankyou!
3.45×10^6 + 1.3×10^5 = 3.45×10^6 + 0.13×10^6 = 3.58×10^6
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An empty dump truck weighs about 2.8×10^5 pounds. How much does it weigh if 15,300 pounds of trash is added? The answer should be in scientific notation.(1 point)
To find the weight of the dump truck with the added trash, we can simply add the weights together:
2.8×10^5 + 15,300 = 2.8×10^5 + 1.53×10^4
To add these in scientific notation, we need to align the exponents. Since 10^5 and 10^4 have the same base, we can add the coefficients:
2.8 + 1.53 = 4.33
The final answer is 4.33×10^5 pounds.
The half-life of uranium-235 is 700,000,000 years. The half-life of uranium-238 is 4.463×10^11 years longer. What is the half-life of uranium-238? The answer should be in decimal form.(1 point)
To find the half-life of uranium-238, we need to add the given time difference to the half-life of uranium-235:
700,000,000 + 4.463×10^11
To add these numbers, we need to convert the coefficient of 10^11 (4.463) into standard decimal form. This means moving the decimal point 11 places to the left:
4.463×10^11 = 0.0000000004463
Now, we can add the two values:
700,000,000 + 0.0000000004463 ≈ 700,000,000
Therefore, the half-life of uranium-238 is approximately 700,000,000 years in decimal form.
whats the answer?
I apologize for the confusion in my previous response. The correct answer is the sum of the half-life of uranium-235 (700,000,000 years) and the additional time (4.463×10^11 years).
700,000,000 + 4.463×10^11 = 446,300,000,000 + 446,300,000,000 = 892,600,000,000 years
Therefore, the half-life of uranium-238 is approximately 892,600,000,000 (or 8.926×10^11) years.
umm sorry but the options above dont give this answer
Apologies for the confusion. Let's try to solve it again:
The half-life of uranium-235 is 700,000,000 years, and the half-life of uranium-238 is 4.463×10^11 years longer.
To find the half-life of uranium-238, we need to add the given time difference to the half-life of uranium-235:
700,000,000 + 4.463×10^11
To add these numbers, we need to convert the coefficient of 10^11 (4.463) into standard decimal form. This means moving the decimal point 11 places to the right:
4.463×10^11 = 446,300,000,000
Now, we can add the two values:
700,000,000 + 446,300,000,000 = 447,000,000,000
Therefore, the half-life of uranium-238 is approximately 447,000,000,000 years in decimal form.
Ok now its right! thank you
You're welcome! I apologize for the confusion earlier. I'm glad we were able to arrive at the correct answer. If you have any more questions, feel free to ask.
A mobile phone holds 1.28×10^11 bytes of storage. You can also pay more money to get an additional 384,000,000,000 bytes. How much storage would your phone have if you buy the additional bytes? The answer should be in scientific notation.(1 point)
To find the total storage of the phone after buying the additional bytes, we need to add the current storage (1.28×10^11 bytes) to the additional storage (384,000,000,000 bytes):
1.28×10^11 + 384,000,000,000
To add these numbers, we need to convert the coefficient of 384,000,000,000 into scientific notation. This means moving the decimal point to the right until we have a number between 1 and 10:
384,000,000,000 = 3.84×10^11
Now we can add the values:
1.28×10^11 + 3.84×10^11 = 5.12×10^11 bytes
Therefore, the phone would have approximately 5.12×10^11 bytes of storage if you buy the additional bytes.