Add: (2m-3)+(3n-1)+(3m+1)

wrong

I apologize for the mistake.

Let's go through the addition step by step:

(2m - 3) + (3n - 1) + (3m + 1)

First, we add the terms with m:
2m + 3m = 5m

Next, let's add the constant terms: -3 + (-1) + 1 = -3

Lastly, we add the terms with n: 3n

Putting it all together, we have:

(2m - 3) + (3n - 1) + (3m + 1) = 5m + 3n - 3

Subtract: 2(10b+4)-(b-2)

To solve the expression 2(10b + 4) - (b - 2), we will follow the order of operations, also called PEMDAS.

First, let's simplify the expressions inside the parentheses:

2(10b + 4) = 20b + 8

Next, distribute the negative sign to the terms inside the parentheses:

-(b - 2) = -b + 2

Now, we can rewrite the expression with the simplified forms:

2(10b + 4) - (b - 2) = 20b + 8 - (b - 2)

Now, distribute the negative sign inside the parentheses:

20b + 8 - b + 2 = 20b - b + 8 + 2

Combine like terms:
(20b - b) + (8 + 2) = 19b + 10

Therefore, the final answer is 19b + 10.

Subtract: (3g-4)-2(3g+4)

To subtract (3g - 4) - 2(3g + 4), we will follow the order of operations, also known as PEMDAS.

First, let's simplify the expression inside the parentheses:

2(3g + 4) = 6g + 8

Now, we can rewrite the original expression with the simplified form:

(3g - 4) - 2(3g + 4) = 3g - 4 - (6g + 8)

Next, distribute the negative sign to the terms inside the parentheses:

3g - 4 - 6g - 8 = 3g - 6g - 4 - 8

Combine like terms:

(3g - 6g) + (-4 - 8) = -3g - 12

Therefore, the final answer is -3g - 12.

Use the properties of operations to add 9(k+1/3)+10(1/2k-1)

To add 9(k + 1/3) + 10(1/2k - 1), we can use the distributive property of multiplication over addition/subtraction. This states that a(b + c) = ab + ac.

First, let's apply the distributive property to each term:

9(k + 1/3) = 9k + 9(1/3) = 9k + 3

10(1/2k - 1) = 10(1/2k) - 10(1) = 5k - 10

Now, we can add the simplified terms together:

9k + 3 + 5k - 10

Combine like terms: 9k + 5k + 3 - 10 = 14k - 7

Therefore, the final answer is 14k - 7.

Use the properties of operations to add 4 (g-2)+(g+2)

To add 4(g - 2) + (g + 2), we can use the distributive property of multiplication over addition/subtraction. This states that a(b + c) = ab + ac.

First, let's apply the distributive property to each term:

4(g - 2) = 4g - 8

(g + 2) remains unchanged.

Now, we can add the simplified terms together:

4g - 8 + g + 2

Combine like terms: 4g + g - 8 + 2 = 5g - 6

Therefore, the final answer is 5g - 6.