The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score: 55, 60, 65, 70, 75, 80, 85, 90
Number of Students: 1, 5, 6, 1, 7, 7, 2, 9
To find the mean score, we need to first calculate the sum of all the scores multiplied by their corresponding number of students:
(55 x 1) + (60 x 5) + (65 x 6) + (70 x 1) + (75 x 7) + (80 x 7) + (85 x 2) + (90 x 9) = 3190
Then, we need to find the total number of students:
1 + 5 + 6 + 1 + 7 + 7 + 2 + 9 = 38
Finally, we can find the mean score by dividing the sum of scores by the number of students:
3190 / 38 = 84.21
Rounding this to the nearest 10th gives us a mean score of 84.2.
To find the mean of the scores, we need to calculate the sum of all the scores first. We can do this by multiplying each score by the corresponding number of students and summing the results:
(55 * 1) + (60 * 5) + (65 * 6) + (70 * 1) + (75 * 7) + (80 * 7) + (85 * 2) + (90 * 9) = 55 + 300 + 390 + 70 + 525 + 560 + 170 + 810 = 2870
Next, we need to find the total number of students by summing all the numbers of students:
1 + 5 + 6 + 1 + 7 + 7 + 2 + 9 = 38
Now, we can find the mean by dividing the sum of the scores by the total number of students:
Mean = Sum of scores / Total number of students
= 2870 / 38
≈ 75.53
Therefore, the mean of the scores to the nearest tenth is approximately 75.5.