The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score: 60, 65, 70, 75, 80, 85, 80, 95
Number of students: 9, 5, 1, 6, 2, 3, 1, 4
To find the mean, we need to first find the sum of all the scores, multiplied by the number of students who received each score.
(60 x 9) + (65 x 5) + (70 x 1) + (75 x 6) + (80 x 2) + (85 x 3) + (80 x 1) + (95 x 4) = 3915
Then we need to divide that sum by the total number of students:
9 + 5 + 1 + 6 + 2 + 3 + 1 + 4 = 31
3915 / 31 = 126.29
To the nearest 10th, the mean score is 126.3.
To find the mean (average) of the scores, we need to calculate the sum of all the scores and then divide it by the total number of students.
First, let's create a table to represent the scores and the number of students:
| Score | Number of Students |
|-------|------------------|
| 60 | 9 |
| 65 | 5 |
| 70 | 1 |
| 75 | 6 |
| 80 | 2 |
| 85 | 3 |
| 90 | 1 |
| 95 | 4 |
Now, let's calculate the sum of all the scores:
(60 * 9) + (65 * 5) + (70 * 1) + (75 * 6) + (80 * 2) + (85 * 3) + (90 * 1) + (95 * 4) = 1915
Next, let's calculate the total number of students:
9 + 5 + 1 + 6 + 2 + 3 + 1 + 4 = 31
Now, let's calculate the mean by dividing the sum of the scores by the total number of students:
Mean = 1915 / 31 ≈ 61.8
Therefore, the mean of the scores to the nearest tenth is approximately 61.8.