A bucket contains the following vegetables 1 squash, 2 carrots, 4 heads of broccoli, 2 artichoke and 5 green beans. Ronnie picks a vegetable at random and does not replace it. Sidney pick a vegetable at random what is the probability that Ronnie gets a carrot and Sydney gets a green bean? Please help someone!!
There are a total of 1+2+4+2+5=14 vegetables in the bucket.
The probability that Ronnie picks a carrot on the first pick is 2/14 or 1/7. Since Ronnie does not replace the vegetable, there are now only 13 vegetables left in the bucket.
The probability that Sydney picks a green bean on the second pick is 5/13.
To find the probability of both events happening in sequence, we need to multiply their individual probabilities:
(1/7) x (5/13) = 5/91
Therefore, the probability that Ronnie picks a carrot and Sydney picks a green bean is 5/91.
To find the probability that Ronnie gets a carrot and Sidney gets a green bean, we need to calculate the probability of each event happening and then multiply them together.
First, let's find the probability that Ronnie gets a carrot.
There are a total of 1 + 2 + 4 + 2 + 5 = 14 vegetables in the bucket.
The probability of Ronnie picking a carrot is 2/14, as there are 2 carrots in the bucket.
Next, let's find the probability that Sidney gets a green bean.
After Ronnie picks a vegetable, there are 14 - 1 = 13 vegetables left in the bucket.
The probability of Sidney picking a green bean is 5/13, as there are 5 green beans remaining in the bucket.
To find the probability of both events happening, we multiply the probabilities:
Probability = (2/14) * (5/13) = 10/182 = 5/91
Therefore, the probability that Ronnie gets a carrot and Sidney gets a green bean is 5/91.
To calculate the probability that Ronnie gets a carrot and Sydney gets a green bean, we need to consider the total number of vegetables in the bucket and the number of carrots and green beans specifically.
Step 1: Count the total number of vegetables in the bucket.
In this case, the bucket contains 1 squash, 2 carrots, 4 heads of broccoli, 2 artichokes, and 5 green beans. So, the total number of vegetables is 1 + 2 + 4 + 2 + 5 = 14.
Step 2: Calculate the probability of Ronnie getting a carrot.
Since there are 2 carrots in the bucket, the probability of Ronnie getting a carrot is 2/14, which can be simplified to 1/7.
Step 3: Calculate the remaining number of vegetables after Ronnie picks a carrot.
After Ronnie picks a carrot, there are now 13 vegetables left in the bucket (as Ronnie does not replace the vegetable).
Step 4: Calculate the probability of Sidney getting a green bean.
Since there are 5 green beans out of the remaining 13 vegetables, the probability of Sidney getting a green bean is 5/13.
Step 5: Multiply the individual probabilities to get the joint probability.
To find the probability that Ronnie gets a carrot and Sidney gets a green bean, multiply the probability from Step 2 (1/7) by the probability from Step 4 (5/13): (1/7) * (5/13).
Step 6: Simplify the calculation and express the answer as a fraction or decimal.
To simplify, you can multiply the numerators (1 * 5) and the denominators (7 * 13). This gives you 5/91 as the probability that Ronnie gets a carrot and Sidney gets a green bean.
Therefore, the probability that Ronnie gets a carrot and Sidney gets a green bean is 5/91.