Of 120 cars taking roadworthiness test, 60% passed. Of the number that fails fault in brakes , light and steering occured as followed;
Brake only =14
Brake and steering = 7
Brake, steering and light = 4
Brake and light = 10
Steering and light only = 3
1. Illustrate the information on a venue
diagram
2. How many cars had faulty light
3. How many cars had only one fault
It is called a Venn diagram, not a Venue diagram.
The bot had:
Failed = 48 , correct
filling in the Venn diagram, we have to start with
Brake, steering and light faults as 4, by filling in the intersection of all 3 with 4
fill in the brake only as 14, I did that
fill in the brake and steering = 7 .... brake and steering ONLY as 3, we already have 4 counted.
fill in the the brake and light = 10 ... brake and light ONLY as 6, we already have 4 of the 10 counted.
fill in the steering and light only with 3 as given.
this leaves the light ONLY and the steering ONLY as the missing parts.
let's add up what we have so far:
14+6+4+3 + 3 = 30
leaving us with 48-30 or 18 for the light only and the steering only combined.
Since no other information is given, we cannot answer the question that
was asked.
1. Venue diagram:
Passed: 72
Failed: 48
- Brake Only: 14
- Brake and Steering: 7
- Brake, Steering and Light: 4
- Brake and Light: 10
- Steering and Light Only: 3
2. The number of cars with faulty light is 17 (Brake and Light: 10, Brake, Steering and Light: 4, Steering and Light Only: 3).
3. The number of cars with only one fault is 21 (Brake Only: 14, Brake and Steering: 7).