Find the surface area of the cylinder to the nearest tenth of a square unit use 3.14 for n. Top 4.6in. Side 9.1in.
The surface area of a cylinder is given by the formula:
2πr^2 + 2πrh
where r is the radius of the circular base and h is the height of the cylinder.
In this case, we are given that the top (which is also the base) has a radius of 4.6 inches and the height of the cylinder is 9.1 inches.
Plugging these values into the formula, we get:
2(3.14)(4.6)^2 + 2(3.14)(4.6)(9.1)
Simplifying this expression, we get:
(2)(3.14)(4.6)(4.6 + 9.1)
= 2(3.14)(4.6)(13.7)
= 645.2
Therefore, the surface area of the cylinder is approximately 645.2 square inches to the nearest tenth of a square inch.