Find the surface area of the cylinder to the nearest tenth of a square unit. Use 3.14 for π.
A cylinder is shown with height 7.8 feet and radius 4.9 feet.
A. 38.2 ft2
B. 75.4 ft2
C. 286.2 ft2
D. 390.8 ft its a cilinder and th hight is 7.8 mildille of the cillinder is 4.9
Guys don't get mad just sit back and observe and let it go be chill 🤙
390.8
circumference is C
radius is r
width is w
length is l
Area is A
C = 2(3.14)(r) = 6.28(4.9) = 30.772
Think of a cylinder as a rectangle attached to two circles, with a length of the height of the 3D figure and a width of the circles' circumferences. Thus, the area for the rectangle is
A = wl = 30.772(7.8) = 240.0216 = ~240 ft^2
Thus, the area for both of the circles combined is
2A = 2(3.14)r^2 = (6.28)(4.9)^2 = 150.7828 = ~150.8 ft^2
Thus, both the areas of the "rectangle" and two "circles" combined make the surface area
240 ft^2 + 150.8 ft^2 = 390.8 ft^2
That is all.
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