A room has three lightbulbs. Each one has a 14%
probability of burning out within the month. Write each probability as a percentage.
What is the probability that at the end of the month at least one of the bulbs will be lit?
Each bulb has a probability of 86% of not burning out within a month (100% - 14% = 86%).
Using this information, we can find the probability that all three bulbs will remain lit:
P(all bulbs remain lit) = 0.86 x 0.86 x 0.86 = 0.636 = 63.6%
Therefore, the probability that at least one of the bulbs will burn out is:
P(at least one bulb burns out) = 1 - P(all bulbs remain lit)
P(at least one bulb burns out) = 1 - 0.636 = 0.364 = 36.4%
So, the probability that at least one bulb will be lit at the end of the month is 36.4%.